Introduction
In this demo I have used NetBeans IDE 8.2 for debugging purpose. But you can use any java programming language compiler as per your availability..
import java.util.Scanner;
public class Javaexcercise {
public static void main(String args[])
{
int decimalnum, quot, i=1, j;
int bin_num[] = new int[100];
Scanner scan = new Scanner(System.in);
System.out.print("Enter a Decimal Number : ");
decimalnum = scan.nextInt();
quot = decimalnum;
while(quot != 0)
{
bin_num[i++] = quot%2;
quot = quot/2;
}
System.out.print("Binary number is: ");
for(j=i-1; j>0; j--)
{
System.out.print(bin_num[j]);
}
System.out.print("\n");
}
}
Result
package myfirstpackage;
import java.util.Scanner;
public class experiment {
public static void main(String[] args) {
int num, harry;
Scanner sc = new Scanner(System.in);
System.out.println(“Please Enter the Decimal Number :”);
num = sc.nextInt();
while (num>0)
{
harry = num % 2;
System.out.print(harry);
num = num/2;
}
}
}
i got the same result of Decimal to Binary Number.
I think so that it is easy code. And main thing is that i performed this code without having array in my code. Rather than, i executed the same ans using just two numbers. If there is any error, so please email me:
[email protected]
This code is incorrect, giving incorrect output
Please check and correct it
Hi, I have rechecked the code is working fine. What’s the issue you are facing?
Not your code.
Hamza’s code is incorrect. It gives 00101 as the binary number for 20, which should be 10100.