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Introduction
Pattern printing in C Programming Language is always a favorite topic for all new c programmers. It mainly focuses on outer & inner loops. In this article, I have explained the list of all alphabet pattern programs in c programming language. I have used Code::Blocks IDE for debugging purpose. But you can use any C programming language compiler as per your availability.
Alphabet Pattern programs in C using for loop
C Language Alphabet pattern 1
A BB CCC DDDD EEEEE
#include<stdio.h>
void main()
{
int i, j;
for(i=1;i<=5;i++)
{
for(j=1;j<=i;j++)
{
printf("%c",'A'-1 + i);
}
printf("\n");
}
}
C Language Alphabet pattern 2
AAAAA BBBB CCC DD E
#include<stdio.h>
void main()
{
int i, j;
for(i=1;i<=5;i++)
{
for(j=5;j>=i;j--)
{
printf("%c",'A'-1 + i);
}
printf("\n");
}
}
C Language Alphabet pattern 3
A AB ABC ABCD ABCDE
#include <stdio.h>
int main()
{
int i, j;
for(i=1;i<=5;i++)
{
for(j=1;j<=i;j++)
{
printf("%c",'A' + j-1);
}
printf("\n");
}
return 0;
}
C Language Alphabet pattern 4
E DE CDE BCDE ABCDE
#include <stdio.h>
int main()
{
int i, j;
for(i=5;i>=1;i--)
{
for(j=i;j<=5;j++)
{
printf("%c",'A' + j-1);
}
printf("\n");
}
return 0;
}
C Language Alphabet pattern 5
A BA CBA DCBA EDCBA
#include <stdio.h>
int main()
{
int i, j;
for(i=1;i<=5;i++)
{
for(j=i;j>=1;j--)
{
printf("%c",'A' + j-1);
}
printf("\n");
}
return 0;
}
C Language Alphabet pattern 6
E ED EDC EDCB EDCBA
#include <stdio.h>
int main()
{
int i, j;
for(i=5;i>=1;i--)
{
for(j=5;j>=i;j--)
{
printf("%c",'A' + j-1);
}
printf("\n");
}
return 0;
}
C Language Alphabet pattern 7
E DD CCC BBBB AAAAA
#include <stdio.h>
int main()
{
int i, j;
for(i=5;i>=1;i--)
{
for(j=5;j>=i;j--)
{
printf("%c",'A'-1 + i);
}
printf("\n");
}
return 0;
}
C Language Alphabet pattern 8
EEEEE DDDD CCC BB A
#include <stdio.h>
int main()
{
int i, j;
for(i=5;i>=1;i--)
{
for(j=1;j<=i;j++)
{
printf("%c",'A'-1 + i);
}
printf("\n");
}
return 0;
}
Alphabet pattern 9
EDCBA EDCB EDC ED E
#include <stdio.h>
int main()
{
int i, j;
for(i=1;i<=5;i++)
{
for(j=5;j>=i;j--)
{
printf("%c",'A'-1 + j);
}
printf("\n");
}
return 0;
}
C Language Alphabet pattern 10
EDCBA DCBA CBA BA A
#include <stdio.h>
int main()
{
int i, j;
for(i=5;i>=1;i--)
{
for(j=i;j>=1;j--)
{
printf("%c",'A'-1 + j);
}
printf("\n");
}
return 0;
}
C Language Alphabet pattern 11
A
ABA
ABCBA
ABCDCBA
ABCDEDCBA
#include<stdio.h>
void main()
{
int ch=65;
int i,j,k,m;
for(i=1;i<=5;i++)
{
for(j=5;j>=i;j--)
printf(" ");
for(k=1;k<=i;k++)
printf("%c",ch++);
ch--;
for(m=1;m<i;m++)
printf("%c",--ch);
printf("\n");
ch=65;
}
}
C Language Alphabet pattern 12
I IN IND INDI INDIA
#include<stdio.h>
void main()
{
char s[]="INDIA";
int i,j;
for(i=0;s[i];i++)
{
for(j=0;j<=i;j++)
printf("%c",s[j]);
printf("\n");
}
}
C Language Alphabet pattern 13
1A2B3C4D5E 1A2B3C4D 1A2B3C 1A2B 1A
#include <stdio.h>
int main()
{
int i,j,k;
for(i=5; i>=1; i--)
{
for(j=1, k='A'; j<=i; j++,k++)
{
printf("%d%c",j,k);
}
printf("\n");
}
return 0;
}
C Language Alphabet pattern 14
A
BAB
CBABC
DCBABCD
EDCBABCDE
#include <stdio.h>
int main()
{
int i,j;
char CH='A';
int space=4;
for(i=1; i<=5; i++)
{
for(j=1; j<=space; j++)
printf(" ");
//first part of the row
for(j=CH; j>='A'; j--)
printf("%c",j);
//second part of the row
for(j='B'; j<=CH; j++)
printf("%c",j);
printf("\n");
CH++;
space--;
}
return 0;
}
C Language Alphabet pattern 15
ABCDEFGFEDCBA ABCDEF FEDCBA ABCDE EDCBA ABCD DCBA ABC CBA AB BA A A
#include<stdio.h>
int main()
{
int i,j,k,l,m;
for(i=0;i<=6;i++)
{
for(k=65;k<=71-i;k++)
printf("%c",k);
for(j=1;j<=i*2-1;j++)
printf(" ");
for(l=71-i;l>=65;l--)
if(l!=71)
printf("%c",l);
printf("\n");
}
return 0;
}
C Language Alphabet pattern 16
A BC DEF GHIJ KLMNO
#include <stdio.h>
int main()
{
int i,j;
char ch='A';
for(i=1;i<=5;i++)
{
for(j=1;j<=i;j++)
{
printf("%c ",ch++);
}
printf("\n");
}
return 0;
}
Alphabet pattern 17
A
BAB
CBABC
DCBABCD
EDCBABCDE
#include<stdio.h>
void main()
{
int i,n=5,j;
for(i=1;i<=n;i++)
{
for(j=1;j<=n-i;j++)
{
printf(" ");
}
for(j=i;j>0;j--)
{
printf(" %c",(char)(j+64));
}
for(j=2;j<=i;j++)
{
printf(" %c",(char)(j+64));
}
printf("\n");
}
}
C Language Alphabet pattern 18
A BF CGJ DHKM EILNO
#include<stdio.h>
void main()
{
int i,j,diff,value,n=5;
for(i=1;i<=n;i++)
{
diff=n-1;
value=i;
for(j=1; j<=i; j++)
{
printf("%4c",(char)(value+64));
value=value+diff;
diff--;
}
printf("\n");
}
}
C Language Alphabet pattern 19
A ABC ABCDE ABCDEFG ABCDEFGI
#include<stdio.h>
void main()
{
int i,j,n=5;
for(i=1;i<=n;i++)
{
for(j=1;j<=(i*2-1);j++)
{
printf("%c",(char)(j+64));
}
printf("\n");
}
}
C Language Alphabet pattern 20
EFGHI DEFG CDE BC A
#include<stdio.h>
void main()
{
int i,j,k,n=5;
for(i=n;i>=1;i--)
{
k = i;
for(j=1;j<=i;j++,k++)
{
printf("%c",(char)(k+64));
}
printf("\n");
}
}
C Language Alphabet pattern 21
ABCDE BCDE CDE DE E
#include<stdio.h>
void main()
{
int i,j,n=5;
for(i=1;i<=n;i++)
{
for(j=i;j<=n;j++)
{
printf("%c",(char)(j+64));
}
printf("\n");
}
}
C Language Alphabet pattern 22
A
BB
CCC
DDDD
EEEEE
#include<stdio.h>
void main()
{
int i,j,k,n=5;
for(i=1;i<=n;i++)
{
for(j=1;j<=n-i;j++)
{
printf(" ");
}
for(k=1;k<=i;k++)
{
printf("%c",(char)(i+64));
}
printf("\n");
}
}
C Language Alphabet pattern 23
A
ABA
ABCBA
ABCDCBA
ABCDEDCBA
#include<stdio.h>
void main()
{
int i,n,j;
for(i=1;i<=5;i++)
{
for(j=1;j<=5-i;j++)
{
printf(" ");
}
for(j=1;j<=i;j++)
{
printf("%c",(char)(j+64));
}
for(j=i-1;j>=1;j--)
{
printf("%c",(char)(j+64));
}
printf("\n");
}
}
C Language Alphabet pattern 24
a Bc DeF gHiJ kLmNo
#include<stdio.h>
void main()
{
int i, j, k = 0, l = 1, n = 5;
for (i = 1; i <= n; i++)
{
for (j = 1; j <= i; j++, k++, l++)
{
if (k % 2 == 0)
{
printf("%4c", (char)(l + 96));
}
else
{
printf("%4c", (char)(l + 64));
}
}
printf("\n");
}
}
C Language Alphabet pattern 25
* *A* *A*A* *A*A*A*
#include<stdio.h>
void main()
{
int i, j;
for(i=1;i<=5;i++)
{
for(j=1;j<=i;j++)
{
if(j%2==0) printf("A");
else printf("*");
}
printf("\n");
}
}
C Language Alphabet pattern 26
AAAAA BBBBB CCCCC DDDDD EEEEE
#include<stdio.h>
void main() {
char i, j;
for (i = 'A'; i <= 'E'; i++) {
for (j = 'A'; j <= 'E'; j++) {
printf("%c", i);
}
printf("\n");
}
}
C Language Alphabet pattern 27
ABCDE ABCDE ABCDE ABCDE ABCDE
#include<stdio.h>
void main() {
char i, j;
for (i = 'A'; i <= 'E'; i++) {
for (j = 'A'; j <= 'E'; j++) {
printf("%c", j);
}
printf("\n");
}
}
C Language Alphabet pattern 28
EEEEE DDDDD CCCCC BBBBB AAAAA
#include<stdio.h>
void main() {
char i, j;
for (i = 'E'; i >= 'A'; i--) {
for (j = 'E'; j >= 'A'; j--) {
printf("%c", i);
}
printf("\n");
}
}
C Language Alphabet pattern 29
EDCBA EDCBA EDCBA EDCBA EDCBA
#include<stdio.h>
void main() {
char i, j;
for (i = 'E'; i >= 'A'; i--) {
for (j = 'E'; j >= 'A'; j--) {
printf("%c", j);
}
printf("\n");
}
}
C Language Alphabet pattern 30
A
BBB
CCCCC
DDDDDDD
EEEEEEEEE
#include<stdio.h>
void main() {
int m = 1;
int p_height = 5;
int p_space = p_height - 1;
int i, j, k;
for (i = 0; i < p_height; i++) {
for (j = p_space; j > i; j--) {
printf(" ");
}
for (k = 0; k < m; k++) {
printf("%c", i + 65);
}
m += 2;
printf("\n");
}
}
C Language Alphabet pattern 31
#include<stdio.h>
void main() {
int m = 0;
int p_height = 5;
int p_space = p_height - 1;
int i, j, k;
for (i = 0; i < p_height; i++) {
for (j = p_space; j > i; j--) {
printf(" ");
}
for (k = 0; k <= m; k++) {
printf("%c", m + 65); // 65 is the ASCII of 'A'
}
m += 2;
printf("\n");
}
}
Also check
A
BC
CDE
DEFG
Aa
Aa Bb
Aa Bb Cc
Aa Bb Cc Dd
Print this
Try This code
#include
main()
{
int i,j;
char c;
for(i=1;i<5;i++)
{
c='A';
for(j=1;j<=i;j++,c++) { printf("%c%c\t",c,c+32); } printf("\n"); } }
#include
int main() {
int i,j,k=0,l=1,n=5;
for(i=0;i<=n;++i){
for(j=0;j<=i;++j)
printf("%c%c",'A'+j,'a'+j);
printf("\n");
}
}
try this .it is working
How to print this pattern in C language?
aA
aabD
aaabb*G
aaaabbb**J
aaaaabbbb***M
aaaaaabbbbb****P
A
b c
D E F
g h i j
K L M N O
print this.
#include
int main() {
int i,j,k=0,l=1,n=5;
for(i=0;i<=n;++i){
for(j=0;j<=i;++j)
if(i%2==0){
printf("%c",'A'+j);
}
else{
printf("%c",'a'+j);
}
printf("\n");
}
}
this code is working like that .check it
a
b C
d E f
g H i j
k L m N o
print this.
#include
int main() {
int i,j,n=5;
char ch=’a’;
char cn=’A’;
for(i=0;i<=n;++i){
for(j=0;j<=i;++j)
if(j%2==0){
printf("%c ",++ch-1,++cn);
}else{
printf("%c ",++cn-1,++ch);
}
printf("\n");
}
}
try this code.it is working
#include
int main() {
int i,j,n=5;
char ch=’a’;
char cn=’A’;
for(i=0;i<=n;++i){
for(j=0;j<=i;++j)
if(j%2==0){
printf("%c ",++ch-1,++cn);
}else{
printf("%c ",++cn-1,++ch);
}
printf("\n");
}
}
use this code .this prints that
1
0 1
0 1 0
1 0 1 0
1 0 1 0 1
print this.
A B C D E
A B C D
A B C
A B
A
Plz print this program.
for(i=5;i>=1;i–)
{
for(j=1;j<=i;j++)
{
printf("%c",'A' + j-1);
}
printf("\n");
}
KLMNO
GHIJ
DEF
BC
A
CAN YOU PLEASE PRINT THIS PATTERN?
i can print only this.
#include
int main() {
int i,j,n=4;
char ch=’P’;
for(i=0;i<=n;++i){
for(j=0;j<=n-i;++j)
printf("%c ",–ch);
printf("\n");
}
}
#include
int main() {
int i,j,n=5;
for(i=n;i>0;–i){
for(j=0;j<=i-1;++j)
printf("%c ",'A'+j);
printf("\n");
}
}
the code is this .use this code
A
ABC
ABCDE
ABCDEFG
ABCDEFGHI
ABCDEFG
ABCDE
ABC
A
use this code .
#include
int main() {
int i,j,value=4;
for(i=0;i<=value;++i){
for(j=0;j<=i*2;++j)
printf("%c ",'A'+j);
printf("\n");
}
for(i=0;i<=value-1;++i){
for(j=0;j<=value-i*2+2;++j)
printf("%c ",'A'+j);
printf("\n");
}
}
A
1. 2.
A. B. C.
1. 2. 3. 4.
Print this
this code is working .just like that
#include
int main() {
int i,j,n=4;
for(i=0;i<=n;++i){
for(j=0;j<=i;++j)
if(i%2==0){
printf("%c.",'A'+j);
}
else{
printf("%d.",+j+1);
}
printf("\n");
}
}
A
b c
D E F
g h i j
K L M N O
print this help
yup. this code just print like that
#include
int main() {
int i,j,n=4;
char ch=’A’;
char cn=’a’;
for(i=0;i<=n;++i){
for(j=0;j<=i;++j)
if(i%2==0){
printf("%c ",++ch-1,++cn);
}
else{
printf("%c ",++cn-1,++ch);
}
printf("\n");
}
}
hey bro do you how to do this pattern
1
121
13231
1432341
A
1 1
B B B
2 2 2 2
C C C C C
Coding for this pattern:-
ZYXWVWXYZ
ZYXWXYZ
ZYXYZ
ZYZ
Z
abcdefghijklmnopqrstuvwxyz
bcdefghijklmnopqrstuvwxyza
…..
……
…
… till
zyxwvutsrqponmlkjihgfedcba
A B C
D E
F
Plz print this urgently
I really need it urgent now